25cm,8mm,times 5
MathBot Answer:
The sum of \(25 c m\) and \(8 m m \cdot 5\) is:
\[\begin{aligned}&=\left(25 c m\right) + \left(8 m m \cdot 5\right) \\\\ &= 25 c m + 8 m m 5 \\\\ &= 5 m \left(5 c + 8 m\right) \\\\\end{aligned}\]
The difference of \(25 c m\) and \(8 m m \cdot 5\) is:
\[\begin{aligned}&=\left(25 c m\right) - \left(8 m m \cdot 5\right) \\\\ &= 25 c m - 8 m m 5 \\\\ &= 5 m \left(5 c - 8 m\right) \\\\\end{aligned}\]
The product of \(25 c m\) and \(8 m m \cdot 5\) is:
\[\begin{aligned}&=\left(25 c m\right) \cdot \left(8 m m \cdot 5\right) \\\\ &= 1000 m^{3} c \\\\\end{aligned}\]
The quotient of \(25 c m\) and \(8 m m \cdot 5\) is:
\[\begin{aligned}&= \frac{\left(25 c m\right)}{\left(8 m m \cdot 5\right)} \\\\ &= \frac{5 c}{8 m} \\\\\end{aligned}\]
asked 10 days ago
active 10 days ago