6(p-q)+4(r-q-p)
asked by guest on Apr 04, 2025 at 2:38 pm
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MathBot Answer:
6(p−q)+4(r−q−p)=2p−10q+4r\displaystyle 6 \left(p - q\right) + 4 \left(r - q - p\right) = 2 p - 10 q + 4 r 6(p−q)+4(r−q−p)=2p−10q+4r
6(p−q)+4(r−q−p)=2p−10q+4r6 \left(p - q\right) + 4 \left(r - q - p\right) = 2 p - 10 q + 4 r6(p−q)+4(r−q−p)=2p−10q+4r