6(p-q)+4(r-q-p)

asked by guest
on Apr 04, 2025 at 2:38 pm



You asked:

Evaluate the expression: 6(pq)+4(rqp)6 \left(p - q\right) + 4 \left(r - q - p\right)

MathBot Answer:

Evaluated



6(pq)+4(rqp)=2p10q+4r\displaystyle 6 \left(p - q\right) + 4 \left(r - q - p\right) = 2 p - 10 q + 4 r


Expanded

6(pq)+4(rqp)=2p10q+4r6 \left(p - q\right) + 4 \left(r - q - p\right) = 2 p - 10 q + 4 r