y′′−6y′+9y=8$e^{x}$
You asked:
Investigate the equation: \(y^{\prime \prime} - 6 \cdot y^{\prime} + 9 y = 8 {e}^{x}\).
MathBot Answer:
\[y{\left(x \right)} = \left(2 + \left(C_{2} x + C_{1}\right) e^{2 x}\right) e^{x}\]
\(C_{1}\), \(C_{2}\) are arbitrary constants.
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).