x^{2}=-y^{2}+398y
You asked:
Investigate the equation: \({x}^{2} = -{y}^{2} + 398 y\).
MathBot Answer:
The graph of the equation \({x}^{2} = -{y}^{2} + 398 y\) is a circle.
The coordinates of its center are \(\left(0, 199\right)\).
Its radius is \(199\).
The cirlce has parameterization: \[\begin{aligned}x\left(\theta\right) &= 199 \cos{\left(\theta \right)}\\y\left(\theta\right) &= 199 + 199 \sin{\left(\theta \right)}\end{aligned}\]