(f∗g)(t)=∫0tcos(aτ)⋅sin(a(t−τ))a,dτ. (f * g)(t) = \int_0^t \cos(a\tau) \cdot \frac{\sin(a(t - \tau))}{a} , d\tau. (f∗g)(t)=∫0tcos(aτ)⋅asin(a(t−τ)),dτ.
asked by guest on Apr 06, 2025 at 6:45 am
