\lim \limits_{x \to \,0} \frac{2x^3}{\sin^3 2x}
You asked:
Evaluate the expression: \(\lim_{x \to 0}{\frac{2 \cdot {x}^{3}}{{\sin\left( 2 x \right)}^{3}}}\)
MathBot Answer:
\[\lim_{x \to 0}{\frac{2 \cdot {x}^{3}}{{\sin\left( 2 x \right)}^{3}}} = \frac{1}{4}\]