λ= $$\frac{8cm𝑙(p+3+α)(p+3+α)^{2}}{h(p+4)}$ (p+3+α)^2/h(p+4)$$
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
λ= $$\frac{8cm𝑙(p+3+α)(p+3+α)^{2}}{h(p+4)}$ (p+3+α)^2/h(p+4)$$
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.