$$\sum_{k=0}^{n-1}{cos(2*k* $\pi$ /n)}$$
You asked:
Evaluate the expression: \(\sum_{k = 0}^{n - 1} {\cos\left( \frac{2 k \cdot \pi}{n} \right)}\)
MathBot Answer:
\[\sum_{k=0}^{n - 1} \cos{\left(\frac{2 k \pi}{n} \right)} = \sum_{k=0}^{n - 1} \cos{\left(\frac{2 k \pi}{n} \right)}\]