(4590-P)×100=P×12×3

asked by guest
on Nov 10, 2024 at 10:44 pm



You asked:

Solve the equation \(\left(4590 - P\right) \cdot 100 = P \cdot 12 \cdot 3\) for the variable \(P\).

MathBot Answer:

The solution is: \[P = 3375\]

\[\begin{aligned}459000 - 100 P &= 36 P\\- 136 P &= -459000\\P &= 3375\end{aligned}\]

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