2x+3y−2\frac{2x+3 }{y-2}y−22x+3, when x= 12\frac{1}{2}21 y=4
asked by guest on Dec 23, 2024 at 7:10 pm
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MathBot Answer:
2x+3y−2=2\frac{2 x + 3}{y - 2} = 2y−22x+3=2
2x+3y−2=3+224−2=3+2⋅124−2=3+2⋅122=3+12=2\begin{aligned}\frac{2 x + 3}{y - 2}&=\frac{3 + \frac{2}{2}}{4 - 2}\\&=\frac{3 + 2 \cdot \frac{1}{2}}{4 - 2}\\&=\frac{3 + 2 \cdot \frac{1}{2}}{2}\\&=\frac{3 + 1}{2}\\&=2\end{aligned}y−22x+3=4−23+22=4−23+2⋅21=23+2⋅21=23+1=2
