(4+1)!=(4+1).5!
You asked:
Investigate the equation: \(\left( 4 + 1 \right)! = \left(4 + 1\right) \cdot .5!\).
MathBot Answer:
This equation has no unknown quantities, so it is either true or false.
This equation is false because the left-hand side is not equal to the right-hand side.
The left-hand side of the equation is:
\[\left( 4 + 1 \right)! = 120\]The right-hand side of the equation is:
\[\left(4 + 1\right) \cdot .5! = 5 \left(\frac{1}{2}\right)!\]