$6^{4-2x}$= 5( $3^{2x-1}$)

asked by guest
on Jan 16, 2025 at 3:57 am



You asked:

Solve the equation \({6}^{4 - 2 x} = 5 \cdot {3}^{2 x - 1}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{- \log{\left(5 \right)} + 4 \log{\left(6 \right)} + \log{\left(3 \right)}}{2 \left(\log{\left(3 \right)} + \log{\left(6 \right)}\right)} \approx 1.1514457\]