-3(y-2)-3(6-y)
asked by guest on Apr 06, 2025 at 4:56 pm
You asked:
MathBot Answer:
−(3(y−2))−3(6−y)=−12\displaystyle -\left( 3 \left(y - 2\right) \right) - 3 \left(6 - y\right) = -12 −(3(y−2))−3(6−y)=−12
−(3(y−2))−3(6−y)=−12-\left( 3 \left(y - 2\right) \right) - 3 \left(6 - y\right) = -12−(3(y−2))−3(6−y)=−12
