$a^{3}$ +2b-2a-2ab=-4/3
2 $a^{2}$ -2b+b $a^{2}$ -2 $b^{2}$ -2 $a^{3}$ +2ab=2/3
You asked:
Solve the system of equations:\[\begin{aligned}{a}^{3} + 2 b - 2 a - 2 a b &= \frac{-4}{3}\\2 \cdot {a}^{2} - 2 b + b \cdot {a}^{2} - 2 \cdot {b}^{2} - 2 \cdot {a}^{3} + 2 a b &= \frac{2}{3}\end{aligned}\]