Math Problem Solver

\[ \frac{3}{10} + \frac{2}{15} + \frac{7}{18} = \frac{37}{45} = 0.8\overline{2} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{10}\), \(\frac{2}{15}\), and \(\frac{7}{18}\) is \(90\). \[ \begin{aligned} \frac{3}{10} + \frac{2}{15} + \frac{7}{18} &= \frac{3 \cdot 9}{10 \cdot 9} + \frac{2 \cdot 6}{15 \cdot 6} + \frac{7 \cdot 5}{18 \cdot 5} \\ &= \frac{27 + 12 + 35}{90} \\ &= \frac{74}{90} \\&= \frac{37}{45} \end{aligned} \]