p=\frac{2ka^4b^3}{\sqrt{c^3}},\:\:p=f\left(a,\:b,\:c\right),\:\:4\%,\:\:3\%,\:\:5\%
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
p=\frac{2ka^4b^3}{\sqrt{c^3}},\:\:p=f\left(a,\:b,\:c\right),\:\:4\%,\:\:3\%,\:\:5\%
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.