4/√10xx-4√10xx-x-45
asked by guest on Nov 23, 2024 at 4:28 pm
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410⋅x⋅x−410⋅x⋅x−x−45=−410x2−x−45+2105x2\displaystyle \frac{4}{\sqrt{10} \cdot x \cdot x} - 4 \sqrt{10} \cdot x \cdot x - x - 45 = - 4 \sqrt{10} x^{2} - x - 45 + \frac{2 \sqrt{10}}{5 x^{2}} 10⋅x⋅x4−410⋅x⋅x−x−45=−410x2−x−45+5x2210
410⋅x⋅x−410⋅x⋅x−x−45=−2010x4+5x3+225x2−2105x2\frac{4}{\sqrt{10} \cdot x \cdot x} - 4 \sqrt{10} \cdot x \cdot x - x - 45 = - \frac{20 \sqrt{10} x^{4} + 5 x^{3} + 225 x^{2} - 2 \sqrt{10}}{5 x^{2}}10⋅x⋅x4−410⋅x⋅x−x−45=−5x22010x4+5x3+225x2−210