10/6+2x+3/x+3-2x/x+3

asked by guest
on Apr 10, 2025 at 1:03 am



You asked:

Evaluate the expression: 106+2x+3x+3−2xx+3\frac{10}{6} + 2 x + \frac{3}{x} + 3 - \frac{2 x}{x} + 3

MathBot Answer:

Evaluated



106+2x+3x+3−2xx+3=2x+173+3x\displaystyle \frac{10}{6} + 2 x + \frac{3}{x} + 3 - \frac{2 x}{x} + 3 = 2 x + \frac{17}{3} + \frac{3}{x}

Factored

106+2x+3x+3−2xx+3=6x2+17x+93x\frac{10}{6} + 2 x + \frac{3}{x} + 3 - \frac{2 x}{x} + 3 = \frac{6 x^{2} + 17 x + 9}{3 x}

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