F(x) = (3x(x-1))/(x^2-3x+2) for x!=1,2
F(1) = -3
F(2) = 4
then f(x) is continuous...
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
F(x) = (3x(x-1))/(x^2-3x+2) for x!=1,2
F(1) = -3
F(2) = 4
then f(x) is continuous...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.