1−(2/3)^𝑛>0.9
asked by guest on Nov 26, 2024 at 8:38 pm
You asked:
MathBot Answer:
n>−log(10)−log(3)+log(2)n > - \frac{\log{\left(10 \right)}}{- \log{\left(3 \right)} + \log{\left(2 \right)}}n>−−log(3)+log(2)log(10)