y = x^2/3 + 0.9 sin (kx) √3 - x^2

asked by guest
on Nov 22, 2024 at 5:27 pm



You asked:

Investigate the equation: \(y = \frac{{x}^{2}}{3} + 0.9 \cdot \sin\left( k x \right) \cdot \sqrt{3} - {x}^{2}\).

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