\int \:ln\left(1-x\right)dx
You asked:
Evaluate the integral: \(\int{\ln\left( 1 - x \right)}dx\)
MathBot Answer:
Antiderivative
\[\int{\ln\left( 1 - x \right)}dx = - x - \log{\left(-1 + x \right)} + x \log{\left(1 - x \right)} + C\]
\int \:ln\left(1-x\right)dx
You asked:
MathBot Answer:
\[\int{\ln\left( 1 - x \right)}dx = - x - \log{\left(-1 + x \right)} + x \log{\left(1 - x \right)} + C\]