(2x-5)^2-[(x+1)(3x-1)]=(x-2)(x+2)-36
You asked:
Solve the equation \({\left( 2 x - 5 \right)}^{2} - \left(x + 1\right) \left(3 x - 1\right) = \left(x - 2\right) \left(x + 2\right) - 36\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = 3\]
\[\begin{aligned}x^{2} - 22 x + 26 &= x^{2} - 40\\- 22 x &= -66\\x &= 3\end{aligned}\]