128+36/71,-206^x

asked by guest
on Jan 25, 2025 at 11:47 pm



MathBot Answer:

The sum of \(128 + \frac{36}{71}\) and \(-{206}^{x}\) is:

\[\begin{aligned}&=\left(128 + \frac{36}{71}\right) + \left(-{206}^{x}\right) \\\\ &= - 206^{x} + \frac{36}{71} + 128 \\\\ &= \frac{9124}{71} - 206^{x} \\\\\end{aligned}\]

The difference of \(128 + \frac{36}{71}\) and \(-{206}^{x}\) is:

\[\begin{aligned}&=\left(128 + \frac{36}{71}\right) - \left(-{206}^{x}\right) \\\\ &= 206^{x} + \frac{36}{71} + 128 \\\\ &= 206^{x} + \frac{9124}{71} \\\\\end{aligned}\]

The product of \(128 + \frac{36}{71}\) and \(-{206}^{x}\) is:

\[\begin{aligned}&=\left(128 + \frac{36}{71}\right) \cdot \left(-{206}^{x}\right) \\\\ &= - 206^{x} \left(\frac{36}{71} + 128\right) \\\\ &= - \frac{9124 \cdot 206^{x}}{71} \\\\\end{aligned}\]

The quotient of \(128 + \frac{36}{71}\) and \(-{206}^{x}\) is:

\[\begin{aligned}&= \frac{\left(128 + \frac{36}{71}\right)}{\left(-{206}^{x}\right)} \\\\ &= - 206^{- x} \left(\frac{36}{71} + 128\right) \\\\ &= - \frac{9124 \cdot 206^{- x}}{71} \\\\\end{aligned}\]

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