sinz /(z-1) ^2 (z^2+9)

asked by guest
on Sep 19, 2024 at 11:15 pm



You asked:

Evaluate the expression: \(\frac{\sin\left( z \right)}{{\left( z - 1 \right)}^{2} \cdot \left({z}^{2} + 9\right)}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{\sin\left( z \right)}{{\left( z - 1 \right)}^{2} \cdot \left({z}^{2} + 9\right)} = \frac{\sin{\left(z \right)}}{\left(z^{2} + 9\right) \left(z - 1\right)^{2}} \)

Expanded

\[\frac{\sin\left( z \right)}{{\left( z - 1 \right)}^{2} \cdot \left({z}^{2} + 9\right)} = \frac{\sin{\left(z \right)}}{z^{4} - 2 z^{3} + 10 z^{2} - 18 z + 9}\]

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