+(x/12)+(x/98)-(4.5)+(x/55)+(0.5x)+(x/114)=0
You asked:
Solve the equation \(\frac{x}{12} + \frac{x}{98} - 4.5 + \frac{x}{55} + 0.5 x + \frac{x}{114} = 0\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{102410}{14121} = 7.\overline{252319240846965512357481764747539126124212166277175837405282911975072586927271439699737978896678705474116563982720770483676793428227462644288648112739890942567806812548686353657672969336449259967424403370866085971248495149068762835493237022873734154804900502797}\]
\[\begin{aligned}\frac{x}{12} + \frac{x}{98} - 4.5 + \frac{x}{55} + 0.5 x + \frac{x}{114} &= 0\\\frac{127089}{204820} x - 4.5 &= 0\\\frac{127089}{204820} x &= 4.5\\x &= \frac{102410}{14121}\end{aligned}\]