+(x/12)+(x/98)-(4.5)+(x/55)+(0.5x)+(x/114)=0

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on Jan 15, 2025 at 3:48 am



You asked:

Solve the equation x12+x98−4.5+x55+0.5x+x114=0\frac{x}{12} + \frac{x}{98} - 4.5 + \frac{x}{55} + 0.5 x + \frac{x}{114} = 0 for the variable xx.

MathBot Answer:

The solution is: x=10241014121=7.252319240846965512357481764747539126124212166277175837405282911975072586927271439699737978896678705474116563982720770483676793428227462644288648112739890942567806812548686353657672969336449259967424403370866085971248495149068762835493237022873734154804900502797‾x = \frac{102410}{14121} = 7.\overline{252319240846965512357481764747539126124212166277175837405282911975072586927271439699737978896678705474116563982720770483676793428227462644288648112739890942567806812548686353657672969336449259967424403370866085971248495149068762835493237022873734154804900502797}

x12+x98−4.5+x55+0.5x+x114=0127089204820x−4.5=0127089204820x=4.5x=10241014121\begin{aligned}\frac{x}{12} + \frac{x}{98} - 4.5 + \frac{x}{55} + 0.5 x + \frac{x}{114} &= 0\\\frac{127089}{204820} x - 4.5 &= 0\\\frac{127089}{204820} x &= 4.5\\x &= \frac{102410}{14121}\end{aligned}

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