M_{q1} = F_{q1} \cdot d_{q1} = 4 \cdot 1 = 4 \, \text{kN·m}
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
M_{q1} = F_{q1} \cdot d_{q1} = 4 \cdot 1 = 4 \, \text{kN·m}
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.