\[\int \frac{(x + 1)^2}{x(x - 1)} \, dx\]
You asked:
Evaluate the integral: \(\int{\frac{{\left( x + 1 \right)}^{2}}{x \cdot \left(x - 1\right)}}dx\)
MathBot Answer:
Antiderivative
\[\int{\frac{{\left( x + 1 \right)}^{2}}{x \cdot \left(x - 1\right)}}dx = - \log{\left(x \right)} + 4 \log{\left(-1 + x \right)} + C + x\]