By changing the order of the integration, evaluate ∫ ∫ xydxdy,
2−x
1
1
0
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
By changing the order of the integration, evaluate ∫ ∫ xydxdy,
2−x
1
1
0
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.