\sum_{n=2}^{\infty}\frac{1}{n(n+2)}

asked by guest
on Oct 06, 2024 at 1:18 am



You asked:

Evaluate the expression: \(\sum_{n = 2}^{\infty} {\frac{1}{n \cdot \left(n + 2\right)}}\)

MathBot Answer:

\[\sum_{n=2}^{\infty} \frac{1}{n \left(n + 2\right)} = \frac{5}{12}\]