x^{2}+y^{2}=20

asked by guest
on Mar 19, 2025 at 4:30 pm



You asked:

Investigate the equation: x2+y2=20{x}^{2} + {y}^{2} = 20.

MathBot Answer:

The graph of the equation x2+y2=20{x}^{2} + {y}^{2} = 20 is a circle.

The coordinates of its center are (0,0)\left(0, 0\right).

Its radius is 252 \sqrt{5}.

The cirlce has parameterization: x(θ)=25cos⁡(θ)y(θ)=25sin⁡(θ)\begin{aligned}x\left(\theta\right) &= 2 \sqrt{5} \cos{\left(\theta \right)}\\y\left(\theta\right) &= 2 \sqrt{5} \sin{\left(\theta \right)}\end{aligned}
    • Axis Limits
    • min x
    • max x
    • min y
    • max y
  • Update Axis Limits
Close Controls

+ Submit Question