find domain of f(x)=1/√2x+1
You asked:
Find domain of \(f\left( x \right) = \frac{1}{\sqrt{2} \cdot x} + 1\)
MathBot Answer:
The domain of \(f(x)=1 + \frac{1}{\sqrt{2} x}\) is \(\left(-\infty, 0\right) \cup \left(0, \infty\right)\).
find domain of f(x)=1/√2x+1
You asked:
MathBot Answer:
The domain of \(f(x)=1 + \frac{1}{\sqrt{2} x}\) is \(\left(-\infty, 0\right) \cup \left(0, \infty\right)\).