6 - 9n + 9n^2

factorize

asked by guest
on Jan 28, 2025 at 2:57 pm



You asked:

Factor the expression: 69n+9n2\displaystyle 6 - 9 n + 9 {n}^{2}

MathBot Answer:

Factorization over the rational numbers:

3(3n23n+2)3 \cdot \left(3 n^{2} - 3 n + 2\right)

Factorization over the complex numbers:

9(n(12+15i6))(n(1215i6))9 \left(n - \left(\frac{1}{2} + \frac{\sqrt{15} i}{6}\right)\right) \left(n - \left(\frac{1}{2} - \frac{\sqrt{15} i}{6}\right)\right)


ii is the imaginary unit, defined as i2=1i^2 = -1.