solve the following equation for x: e^(-2x)-3e^(-x)=-2

asked by guest
on Mar 22, 2025 at 5:02 am



You asked:

Solve the equation e(2x)3ex=2{e}^{-\left( 2 x \right)} - 3 {e}^{-x} = -2 for the unknown xx.

MathBot Answer:

The real solutions are: x=0x=log(2)\begin{aligned}x &=0\\x &=- \log{\left(2 \right)}\end{aligned}


The complex solutions are: x={2πin  |  nZ}{6.2831853ni  |  nZ}x={log(2)+2πin  |  nZ}{6.2831853ni0.69314718  |  nZ}\begin{aligned}x &= \left\{2 \pi i n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n i\; \middle|\; n \in \mathbb{Z}\right\}\\x &= \left\{- \log{\left(2 \right)} + 2 \pi i n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n i - 0.69314718\; \middle|\; n \in \mathbb{Z}\right\}\end{aligned}


ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

ii is the imaginary unit, defined as i2=1i^2 = -1.