= 2^n*(5^n - 1)
asked by guest on Mar 26, 2025 at 7:18 pm
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MathBot Answer:
2n(5n−1)=2n(5n−1)\displaystyle {2}^{n} \left({5}^{n} - 1\right) = 2^{n} \left(5^{n} - 1\right) 2n(5n−1)=2n(5n−1)
2n(5n−1)=10n−2n{2}^{n} \left({5}^{n} - 1\right) = 10^{n} - 2^{n}2n(5n−1)=10n−2n