log4(64) ^ (n + 1) = log5(625) ^ (n - 1)

asked by guest
on Mar 19, 2025 at 5:43 pm



You asked:

Solve the equation log⁡4(64)n+1=log⁡5(625)n−1{\log_{4}\left( 64 \right)}^{n + 1} = {\log_{5}\left( 625 \right)}^{n - 1} for the variable nn.

MathBot Answer:

The solution is: n=log⁡(12)−log⁡(3)+2log⁡(2)≈8.6376834n = \frac{\log{\left(12 \right)}}{- \log{\left(3 \right)} + 2 \log{\left(2 \right)}} \approx 8.6376834

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