6(2x-1)+9(x+1)=8(x-1 $\frac{1}{4}$ )
You asked:
Solve the equation \(6 \cdot \left(2 x - 1\right) + 9 \cdot \left(x + 1\right) = 8 \cdot \left(x - 1\frac{1}{4}\right)\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = -1\]
\[\begin{aligned}21 x + 3 &= 8 x - 10\\13 x &= -13\\x &= -1\end{aligned}\]