6log10((93−x)^2)=22.8

asked by guest
on Nov 27, 2024 at 6:19 am



You asked:

Solve the equation \(6 \cdot \log_{10}\left( {\left( 93 - x \right)}^{2} \right) = 22.8\) for the variable \(x\).

MathBot Answer:

The 2 solutions to the equation are: \[\begin{aligned}x &= 93 - 10 \cdot 10^{\frac{9}{10}} \approx 13.567177\\x &= 93 + 10 \cdot 10^{\frac{9}{10}} \approx 172.43282\end{aligned}\]