Math Problem Solver

\[ 890 - 096=794 \]

\[ \begin{aligned} \overset{\mathtt{{\scriptscriptstyle 7}}}{\cancel{\mathtt{8}}}\overset{\mathtt{{\scriptscriptstyle 18}}}{\cancel{\mathtt{9}}}\overset{\mathtt{{\scriptscriptstyle 10}}}{\cancel{\mathtt{0}}}\\ \mathtt{-\phantom{0}}\phantom{0}\mathtt{9}\mathtt{6}\\ \hline \mathtt{7}\mathtt{9}\mathtt{4} \end{aligned} \]

Borrow \(10^{1}\), resulting in \(8\) in the \(10^{1}\) place, and \(10\) in the \(10^{0}\) place.

\(4\) is the digit in the \(10^{0}\) place. \(10 \times 10^{0} - 6 \times 10^{0} = 4 \times 10^{0}\).

Borrow \(10^{2}\), resulting in \(7\) in the \(10^{2}\) place, and \(18\) in the \(10^{1}\) place.

\(9\) is the digit in the \(10^{1}\) place. \(18 \times 10^{1} - 9 \times 10^{1} = 9 \times 10^{1}\).

\(7\) is the digit in the \(10^{2}\) place. \(7 \times 10^{2} - 0 \times 10^{2} = 7 \times 10^{2}\).