((x/(e^x-1))^2)*(e^x)-0.05=0

asked by guest
on Nov 27, 2024 at 7:28 am



You asked:

Investigate the equation: \({\left( \frac{x}{{e}^{x} - 1} \right)}^{2} {e}^{x} - 0.05 = 0\).

MathBot Answer:


The complex solutions are: \[\left\{x\; \middle|\; x \in \mathbb{R} \wedge 20 x^{2} e^{x} - e^{2 x} + 2 e^{x} - 1 = 0 \right\} \setminus \left\{0\right\}\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).