if x=13-4√3, find √x
asked by guest on Nov 13, 2024 at 10:39 pm
MathBot Answer:
x=13−43\sqrt{x} = \sqrt{13 - 4 \sqrt{3}}x=13−43
x=13−43=−43+13=13−43\begin{aligned}\sqrt{x}&=\sqrt{13 - 4 \sqrt{3}}\\&=\sqrt{- 4 \sqrt{3} + 13}\\&=\sqrt{13 - 4 \sqrt{3}}\end{aligned}x=13−43=−43+13=13−43
