y=x^(2/3)+0.9sin(kx)sqrt(3-x^2)

asked by guest
on Nov 29, 2024 at 5:19 pm



You asked:

Investigate the equation: y=x23+0.9sin⁡(kx)⋅3−x2y = {x}^{\frac{2}{3}} + 0.9 \sin\left( k x \right) \cdot \sqrt{3 - {x}^{2}}.

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