log₃(1 - 2x) - log₃(1 + 4x) = -1
Find the value of x.
You asked:
Solve the equation \[\log_{3}\left( 1 - 2 x \right) - \log_{3}\left( 1 + 4 x \right) = -1\] for the unknown \(x\).
MathBot Answer:
The complex solutions are: \[\left\{x\; \middle|\; x \in \mathbb{R} \wedge e \left(1 - 2 x\right)^{\frac{1}{\log{\left(3 \right)}}} - \left(4 x + 1\right)^{\frac{1}{\log{\left(3 \right)}}} = 0 \right\} \setminus \left\{- \frac{1}{4}\right\}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).