10=80e^x
You asked:
Investigate the equation: \(10 = 80 \cdot {e}^{x}\).
MathBot Answer:
The real solution is: \[x = - \log{\left(8 \right)} \approx -2.0794415\]
The complex solutions are: \[\left\{2 n i \pi - \log{\left(8 \right)}\; \middle|\; n \in \mathbb{Z}\right\}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).
\(i\) is the imaginary unit, defined as \(i^2 = -1\).