(y^2+7xy+16x^2)dx+x^2dy=0

asked by guest
on Nov 14, 2024 at 2:59 am



You asked:

Investigate the equation: \(\left({y}^{2} + 7 x y + 16 \cdot {x}^{2}\right) \cdot d x + {x}^{2} \cdot d y = 0\).

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