187125.32 = 70000 * (1.1)^x * (1.12)^3 * (1.14)^(6-x)
You asked:
Solve the equation \(187125.32 = 70000 \cdot {1.1}^{x} \cdot {1.12}^{3} \cdot {1.14}^{6 - x}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{- 2 \log{\left(36297828 \right)} + \log{\left(1142122314453125 \right)}}{- \log{\left(57 \right)} + \log{\left(55 \right)}} \approx 3.9999997\]