6x to the power of 4 +7x cubed+8x squared+5x-12 over3x squared+2x-3

asked by guest
on Nov 19, 2024 at 8:43 am



You asked:

Evaluate the expression: \(6 \cdot {x}^{4} + 7 \cdot {x}^{3} + 8 \cdot {x}^{2} + 5 x - \frac{12}{3 \cdot {x}^{2}} + 2 x - 3\)

MathBot Answer:

Evaluated



\(\displaystyle 6 \cdot {x}^{4} + 7 \cdot {x}^{3} + 8 \cdot {x}^{2} + 5 x - \frac{12}{3 \cdot {x}^{2}} + 2 x - 3 = 6 x^{4} + 7 x^{3} + 8 x^{2} + 7 x - 3 - \frac{4}{x^{2}} \)

Factored

\[6 \cdot {x}^{4} + 7 \cdot {x}^{3} + 8 \cdot {x}^{2} + 5 x - \frac{12}{3 \cdot {x}^{2}} + 2 x - 3 = \frac{6 x^{6} + 7 x^{5} + 8 x^{4} + 7 x^{3} - 3 x^{2} - 4}{x^{2}}\]

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