consider ivp x'=x^1/2+1 x(0)=0 on the interval 0 to t
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
consider ivp x'=x^1/2+1 x(0)=0 on the interval 0 to t
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.