inverse function of g(x)= 3x23x^{2}+6x+10

asked by guest
on Nov 28, 2024 at 9:30 am



You asked:

Find the inverse of g(x)=3x2+6x+10g\left( x \right) = 3 {x}^{2} + 6 x + 10

MathBot Answer:

For −∞<x≤−1-\infty \lt x \le -1 the inverse is g−1(x)=−3x−213−1g^{-1}\left( x \right) =- \frac{\sqrt{3 x - 21}}{3} - 1
For −1≤x<∞-1 \le x \lt \infty the inverse is g−1(x)=3x−213−1g^{-1}\left( x \right) =\frac{\sqrt{3 x - 21}}{3} - 1

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