inverse function of g(x)= $3x^{2}$+6x+10

asked by guest
on Nov 28, 2024 at 9:30 am



You asked:

Find the inverse of \(g\left( x \right) = 3 {x}^{2} + 6 x + 10\)

MathBot Answer:

For \(-\infty \lt x \le -1\) the inverse is \(g^{-1}\left( x \right) =- \frac{\sqrt{3 x - 21}}{3} - 1\)
For \(-1 \le x \lt \infty\) the inverse is \(g^{-1}\left( x \right) =\frac{\sqrt{3 x - 21}}{3} - 1\)

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