Is (–4, –1) a solution to this system of inequalities?
14x + 14y ≤ –7
6x − 11y ≤ 15
asked by guest on Mar 29, 2025 at 7:07 pm
MathBot Answer:
True, (−4, −1)\left( -4, \ -1\right)(−4, −1) is a solution of 14x+14y≤−7 and 6x−11y≤1514 x + 14 y \leq -7 \text{ and } 6 x - 11 y \leq 1514x+14y≤−7 and 6x−11y≤15.
14x+14y≤−714(−4)+14(−1)≤?−7−70≤−7\begin{gathered}14 x + 14 y \leq -7\\14 \left(-4\right) + 14 \left(-1\right) \stackrel{?}{\le} -7\\-70 \le -7\end{gathered}14x+14y≤−714(−4)+14(−1)≤?−7−70≤−76x−11y≤156(−4)−11(−1)≤?15−13≤15\begin{gathered}6 x - 11 y \leq 15\\6 \left(-4\right) - 11 \left(-1\right) \stackrel{?}{\le} 15\\-13 \le 15\end{gathered}6x−11y≤156(−4)−11(−1)≤?15−13≤15
